Question

number of carbon atoms present in 1.71 g of sugar​

Answer 1

Answer:

Sugar is nothing but sucrose, which has a formula of C₁₂H₂₂O₁₁ and a molecular weight of 342.

number of moles of sucrose in 1.71 grams = 0.005

1 mole of sucrose contains Avogadro number(6 x 10²³) of sucrose molecules.

As each molecule of sucrose has 12 carbon atoms,

1 mole of sucrose contains 12( 6 x 10²³) of carbon atoms.

Therefore 0.005 moles of sucrose contains 0.005 x 12( 6 x 10²³)

                                                                 = 3.6 x 10²² atoms of carbon are     

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Answer 2

Answer:

Explanation:

3.6 x 10 power 22