Chemistry, asked by aditya8289, 9 months ago

Number of carbon atoms present in 1.71g of sugar (C12H22011) ​

Answers

Answered by Tirth7404
3

Answer:

moles=weight/molecular weight

n = 1.71/342

n = 0.005 moles

no. of carbon atoms= 0.005×12×6×10^23

= 0.36×10^23 atoms

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