Question

Number of carbon atoms present in 22g co2 is

Answer 1

Answer : The number of carbon atoms present in 22 g of $CO_2$ is, $3.011\times 10^{23}$

Solution : Given,

Mass of $CO_2$ = 22 g

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $CO_2$.

$\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=\frac{22g}{44g/mole}=0.5moles$

As, 1 mole of $CO_2$ contains $6.022\times 10^{23}$ atoms

So, 0.5 moles of $CO_2$ contains $0.5\times 6.022\times 10^{23}=3.011\times 10^{23}$ atoms

And the number of mole of carbon present in one molecule carbon dioxide is equal to 1 mole.

Therefore, the required number of carbon atoms is, $3.011\times 10^{23}$

Answer 2

Answer:  

the required number of carbon atoms is 3.011 x 10^23.