Number of carbon atoms present in 44g of co2
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Number of carbon atoms present in 44g of co2 is 6.023x10^23.
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First you need to find relative molecular mass. You can calculate it using relative atomic mass of C and O So
MCO2=12+16×2MCO2=12+16×2
=44gmol−1=44gmol−1
molecular mass of CO2CO2 is 44. Which mean 44 grams of CO2CO2contain Avogadro’s number of atoms. So,
44gmol−1=6.022×1023mol−144gmol−1=6.022×1023mol−1(Avogadro’s number)
442=6.022×10232442=6.022×10232
22g=3.011×102322g=3.011×1023
So 22g of CO2CO2have 3.011×10233.011×1023 CO2CO2molecules.
Since one molecule has one carbon atom it also has 3.011×10233.011×1023 Carbon atoms
MCO2=12+16×2MCO2=12+16×2
=44gmol−1=44gmol−1
molecular mass of CO2CO2 is 44. Which mean 44 grams of CO2CO2contain Avogadro’s number of atoms. So,
44gmol−1=6.022×1023mol−144gmol−1=6.022×1023mol−1(Avogadro’s number)
442=6.022×10232442=6.022×10232
22g=3.011×102322g=3.011×1023
So 22g of CO2CO2have 3.011×10233.011×1023 CO2CO2molecules.
Since one molecule has one carbon atom it also has 3.011×10233.011×1023 Carbon atoms
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