Question

number of cation present in 1.12 g of quick lime is?​

Answer 1

Explanation:

The total number of oxygen atoms is 1.2044\times 10^{22}atoms1.2044×10

22

atoms

Mass of quick lime that calcium oxide = 1.12 g

Molar mass of the quick lime = \frac{1.12 g}{56 g/mol}=0.02 mol

56g/mol

1.12g

=0.02mol

Number of molecules of CaO :

0.02 mol\times 6.022\times 10^{23} mol^{-1}=1.2044\times 10^{22} molecules0.02mol×6.022×10

23

mol

−1

=1.2044×10

22

molecules

In one molecule of CaO there is 1 oxygen atom , then number of oxygen atoms in 1.2044\times 10^{22} molecules1.2044×10

22

molecules are:

1\times 1.2044\times 10^{22} =1.2044\times 10^{22} atoms1×1.2044×10

22

=1.2044×10

22

atoms

The total number of oxygen atoms is 1.2044\times 10^{22} atoms1.2044×10

22

atoms

Answer 2

Answer:

Answer:

The total number of oxygen atoms is 1.2044\times 10^{22}atoms1.2044×10

22

atoms

Explanation:

Mass of quick lime that calcium oxide = 1.12 g

Molar mass of the quick lime = \frac{1.12 g}{56 g/mol}=0.02 mol

56g/mol

1.12g

=0.02mol

Number of molecules of CaO :

0.02 mol\times 6.022\times 10^{23} mol^{-1}=1.2044\times 10^{22} molecules0.02mol×6.022×10

23

mol

−1

=1.2044×10 ^22

molecules

In one molecule of CaO there is 1 oxygen atom , then number of oxygen atoms in 1.2044\times 10^{22} molecules1.2044×10 ^22

molecules are:

1\times 1.2044\times 10^{22} =1.2044\times 10^{22} atoms1×1.2044×10 ^22

=1.2044×10 ^22

atoms

The total number of oxygen atoms is 1.2044\times 10^{22} atoms1.2044×10 ^22

atoms