Number of chloride ions in 95 gram of magnesium chloride
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(9.5 g MgC12)* (1 mole MgC12/ 95.211g MgC12)
(6. 022× 10 ^ 23 MgC12 molecules /1 mole MgC12)* (2 CI ions /l molecules MgC12 )
= 1.2 × 10 ^3 chloride ions.
(6. 022× 10 ^ 23 MgC12 molecules /1 mole MgC12)* (2 CI ions /l molecules MgC12 )
= 1.2 × 10 ^3 chloride ions.
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