Question

number of delocalised pi electrons in benzoic acid=---------​

Answer 1

Answer:

Benzoic acid (C7H6O2) has 7(4) + 6(1) + 2(6) = 46 valence electrons. The Lewis structure for benzoic acid is: The circle in the ring indicates the delocalized π bonding in the benzene ring. The two benzene resonance Lewis structures have three alternating double bonds in the ring (see Figure 14.48).

Answer 2

The Number of delocalised pi electrons in benzoic acid contains 15 sigma and 4 pi bond.

Explanation:

• Benzoic acid is an organic compound with the formula C₆H₅COOH.
• It contains one benzene ring with the carboxylic group.
• It is used as a food preservatives
• The general formula is C₇H₆O₂
• It has 7(4)+6(1)+2(6)=46 valence electrons.
• The circle in the benzene ring shows the delocalized pi bonding.
• The two resonance structures of benzene have an alternate double bond.
• Single bonds contain one sigma bond and double bonds contain one sigma and one pi bond and triple bonds contain one sigma and two pi bond.
• Benzoic acid contains 15 sigma and 4 pi bond.