Number of diagonals of polygon which has ( p + 3 ) sides __________.
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Number of diagonals of polygon which has ( p + 3 ) sides are (p² + 3p)/2
Given : A polygon with (p + 3) sides
To Find : number of diagonal
Solution:
A polygon with n sides has diagonals = (n)(n - 3) /2
Now its given that number of sides of polygon are (p + 3)
Hence substituting n = p + 3
Number of Diagonals = (p + 3)(p + 3 - 3)/2
= (p + 3)p/2
=(p² + 3p)/2
Number of diagonals of polygon which has ( p + 3 ) sides are (p² + 3p)/2
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