Question

number of distinct terms in (a+b+c+d+e)^3​

Answer 1

Answer:

$a \times a \times a + b \times b \times b + c \times c \times c$

$+ d \times d \times d + e \times e \times e$

$= 3a + 3b + 3c + 3d + 3e$

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Answer 2

Step-by-step explanation:

Step-by-step explanation:

As DE is parallel to BC, by basic proportionality theorem, AD/DB = AE/EC

=> 3/6 = 4/x

=> 3x = 24 [ by cross multiplication ]

=> x = 24/3 = 8 cm