Question

number of diviser of a natural number by formula​

Answer 1

Answer:

Let d( n ) be the number of divisors for the natural number, n . We begin by writing the number as a product of prime factors: n = p a q b r c ... then the number of divisors, d( n ) = ( a +1)( b +1)( c +1)... To prove this, we first consider numbers of the form, n = p a .

Answer 2

Answer:

Fortunately there is a quick and accurate method using the divisor, or Tau, function. Let d( n ) be the number of divisors for the natural number, n . We begin by writing the number as a product of prime factors: n = p a q b r c ... then the number of divisors, d( n ) = ( a +1)( b +1)( c +1)...

Step-by-step explanation:

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