Number of electron present in 1.6 g of methane is
deviousajeet:
given amount =1.6 g so amount of methane is 1.6/26 mole=0.1 mole..since 1 mole contains 6.022×10^23 therefore answer is 0.1×6.022×10^23=6.022×10^22
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n = 1.6 / 16
no. of electron = n x NA x electron
= 1.6/16 x NA x 10
= NA
so, no of electron = 6.023 x 10^23
hope u understand.....
no. of electron = n x NA x electron
= 1.6/16 x NA x 10
= NA
so, no of electron = 6.023 x 10^23
hope u understand.....
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