Question

Number of electron present in 8 coulamb nagetive charge ​

Answer 1

Answer:

5×10×10×10×10×10×10×10×10×10×10

Answer 2

QUESTION:–

Number of electron present in 8 coulomb negative charge.

ANSWER:–

Charge on 1 electron= 1.6 × ${10}^{-19}$

Number of electron in 1 C of charge

$= \frac{1}{1.6 \times {10}^{ - 19} }$

Number of electrons present in 18 C of charge

$= \frac{1}{1.6 \times {10}^{ - 19} } \times 18 \\ \\ \\ = \frac{18 \times {10}^{19} \times 10}{16} \\ \\ \\ = 9 \times {10}^{19} \times \frac{5}{4} \\ \\ \\ \\ = \frac{45 \times 100 \times {10}^{17} }{4} \\ \\ \\ \\ 45 \times 25 \times {10}^{17} \\ \\ \\ \\ = 1.125 \times {10}^{20} \: electrons$

Points to Remember

• Remember the correct formula
• Do correct calculations
• Verify the result, if required.