Question

Number of electrons in 0.2 moles of NaOH

Answer 1

1 mole of NaOH contains 20 *Na electrons
so 0.2 mole contains 20*Na*0.2 electrons=4*Na
where Na is the avagadros number

Answer 2

Answer : The number of electrons in 0.2 moles of NaOH is $120.44\times 10^{23}$ electrons.

Solution : Given,

Number of moles of NaOH = 0.2 moles

The number of electrons present in 1 molecule of NaOH is,

NaOH = (11) + (6) + (1) = 20 electrons

1 mole of NaOH has $6.022\times 10^{23}$ molecule of NaOH

Number of electrons present in 1 molecule of NaOH = 20 electrons

Number of electrons present in $6.022\times 10^{23}$ molecule of NaOH = $(6.022\times 10^{23})\times (20)=120.44\times 10^{23}$ electrons

Therefore, the number of electrons in 0.2 moles of NaOH is $120.44\times 10^{23}$ electrons.