Number of electrons in 1mole of lithium ion Li+
a) 6.02 × 10^23
b) 1.204 × 10^24
c) 6.02 × 10^21
d) 3.02 × 10^23
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Answer:
number of electrons in a cation = (atomic number - charge )× no of moles × avagadro's number
Explanation:
no of electrons in Li+ = (3-1)× 6.023×10^23
=>12.046×10^23
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