Question

Number of electrons in 3.2gCh4

Answer 1

Hey !

Given,

Quantity of Methane = 3.2g

No. of Electrons = ?

Step-1 :

Find the Total No of moles in 3.2g of methane

Molecular weight of methane (CH4) is 16g.

Total No of moles in 3.2g of methane=given mass/molar mass

=> Total no. of moles in 3.2 g of Methane = 3.2/16=0.2

Step-2:

Find total no. of Electrons in one mole of Methane

1 mole of CH4 contains :

- 1 c atom(6 electrons)

- 4 hydrogen(1×4 electrons)

•°• Total no. of Electrons= 10

Step-3:

Find total no. of Electrons in 3.2 g of methane

We have,

Total no of electrons in a compound = Total no of moles×total no of electons in 1 mole ×(Avagadro’s no)

In 3.2g of Methane,

No. of Electrons = 0.2×10×(6.022×10^23)=

=> No. of Electrons = 2 × 6.022 × 10^ 23

=> No. of Electrons = 12.044×10^23

=> No. of Electrons = 1.2044×10^24

Hence there are 1.2044×10^24 electrons in 3.2 g of methane.

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