Question

Number of electrons involved in the reaction when 0.1 mol nh3 dissolved in water

Answer 1

Number of electrons involved in the reaction when 0.1 mol Ammonia, NH3 dissolved in water, H2O.

Normally what happens is that when you dissolve ammonia in water, we end up forming a basic solution of ammonium hydroxide with a chemical formula of NH4OH.

So to determine the number of electrons in ammoinum hydroxide (now after dissolving), we shall follow these steps.

NH4OH

number of e- in Nitrogen = 7

Number of e- in hydrogen = 1

number of e- in oxygen     = 8

So electrons in NH4OH = 7 + (1 x 5) +8

20 electrons.

Answer 2

Answer:

Explanation:

Zero

Because when Nh3 is dissolved in water, Nh4Oh is formed and the charge on nitrogen in both Nh3 and Nh4oh is -3 so no electrons are transferred or exchanged.

Also,

When NH3 is dissolved in water it isn't a redox reaction so no electron is involved. NH3 + H2O ---> NH4+ + OH- . It is simply exchange of ions from H2O