Number of electrons lost during the electrolysis of0.355grams of chloride ion is??
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no of mole = given wt /molecular wt
given wt = 0.355 g
molecular wt of chloride ions = 35.5 g
So,
no of mole = 0.355/35.5 = 10^-2
we also know ,
no of electrons = no of moles × 6.023 × 10²³
= 10-² × 6.023 × 10²³
= 6.023 × 10²¹
given wt = 0.355 g
molecular wt of chloride ions = 35.5 g
So,
no of mole = 0.355/35.5 = 10^-2
we also know ,
no of electrons = no of moles × 6.023 × 10²³
= 10-² × 6.023 × 10²³
= 6.023 × 10²¹
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