number of electrons present in 0.2 mole of n a o h is
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no. of electrons in 1 molecule of naoh = 11+1+8 =20
total no. of molecules of naoh in 0.2 moles = 0.2×6.022×10 (power23)
for total no. of electron multiply answer with 20
total no. of molecules of naoh in 0.2 moles = 0.2×6.022×10 (power23)
for total no. of electron multiply answer with 20
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