Question

Number of electrons present in 24 g of Mg2+ ions is
(Atomic mass of Mg = 24 u)
a. 2 NA
b. 4 NA
c. NA
d. 10 NA​

Answer 1

Answer:

answer d is correct I means

Answer 2

Answer:

24 gm of Magnesium contains = NA atoms. Where NA  = 6.023 × 10²³

1 atom of Mg contains 12 electrons

Mg²⁺ ion will contain (12-2) = 10 electrons

NA Mg²⁺ ions will contain

= 10 X NA

= 10 X 6.023 X 10²³

⇒ 10 X NA

= 10 NA

So, your answer is d. 10 NA

Explanation:

Hope it helps you buudy :)