Physics, asked by dksingh861, 10 months ago

Number of electrons present in 3.6 mg of nh+4nh4+ are:

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Answered by Anonymous
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Number of electrons present in 3.6 mg of NH4+ are ?(plz give a detailed answer) Since 1 mole of ion contains 6.022 × 1023 atoms of ammonium, so 1 mole of NH4+ will have 6.022 × 1023 × 10 elctrons

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