Question

Number of electrons present in 32 gm of oxide (O–2) ion
A)10 NA
B)5 NA
C)20 NA
D)None

Answer 1

Answer:

Molar mass of oxide ion= 16 gms= 1 mol= Na

Therefore, 32 gms= 2mols= 2 Na

Now 1 mol of oxide ion has (8+2)= 10 electrons*Na

2 mols will have 20 electrons*Na.

Therefore the answer is (c) 20 Na

Explanation:

NOTE:

no. of electrons in the oxide ion is equal to atomic number + charge( if positive charge is given, no. of electrons= atomic number - charge).

Answer 2

Answer:

ok, what we have to find?