Math, asked by g9023281, 2 days ago

number of electrons, protons and neutrons present in 17CI35,17CI is​

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Answered by aamirsohail748299
1

Answer:

number of protons and electrons in a neutral atom is equal to its atomic number. Here atomic number is 17 hence no.of election and protons is 17

No.of neutrons= Atomic mass- Atomic number

hence 35-17=18

so number of neutrons is 18.

Answered by pd6960559
1

Answer:

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