Number of electrons,protons and neutrons present in 17cl35, 17cl37 is
Answers
Answer:
Number of electrons, protons and neutrons present in 17Cl35, 17Cl37 is------a) 17e¯ , 17p+, 17n 17e¯ , 20p+, 19n
b) 18e¯ , 18p+, 17n 17e¯ , 17p+, 19n
c) 17e¯ , 17p+, 18n 20e¯ , 20p+, 17n
d) 18e¯ , 17p+, 18n 17e¯ , 17p+, 20n
Explanation:
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Answer:
₁₇Cl³⁵
Number of protons = 17
Number of Electrons = 17
Number of neutrons = 18
₁₇Cl³⁷
Number of protons = 17
Number of Electrons = 17
Number of neutrons = 20
Explanation:
₁₇Cl³⁵ and ₁₇Cl³⁷ are isotopes of Chlorine
Isotopes are atoms with the same atomic number with different mass numbers.
Here, in these two isotopes of Chlorine, the atomic number is the same and it is equal to 17
Since atomic number is equal to the number of protons or electrons in an atom
Number of protons in both these isotopes = 17
Also, the number of electrons in both these isotopes = 17
The mass number of ₁₇Cl³⁵ = 35
The mass number of ₁₇Cl³⁷ = 37
Since mass number is defined as the sum of protons and neutrons in the nucleus of the atom
In the case of ₁₇Cl³⁵,
Number of protons +Number of neutrons = 35
17 +Number of neutrons = 35
Number of neutrons = 35 -17 = 18
In the case of ₁₇Cl³⁷,
Number of protons +Number of neutrons = 37
17 +Number of neutrons = 37
Number of neutrons = 37 -17 = 20
∴ ₁₇Cl³⁵
Number of protons = 17
Number of Electrons = 17
Number of neutrons = 18
₁₇Cl³⁷
Number of protons = 17
Number of Electrons = 17
Number of neutrons = 20
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