Chemistry, asked by abu552007, 3 days ago

Number of electrons,protons and neutrons present in 17cl35, 17cl37 is​

Answers

Answered by harsha2027
5

Answer:

Number of electrons, protons and neutrons present in 17Cl35, 17Cl37 is------a) 17e¯ , 17p+, 17n 17e¯ , 20p+, 19n

b) 18e¯ , 18p+, 17n 17e¯ , 17p+, 19n

c) 17e¯ , 17p+, 18n 20e¯ , 20p+, 17n

d) 18e¯ , 17p+, 18n 17e¯ , 17p+, 20n

Explanation:

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Answered by smithasijotsl
0

Answer:

₁₇Cl³⁵

Number of protons = 17

Number of Electrons = 17

Number of neutrons = 18

₁₇Cl³⁷

Number of protons = 17

Number of Electrons = 17

Number of neutrons = 20

Explanation:

₁₇Cl³⁵ and ₁₇Cl³⁷ are isotopes of Chlorine

Isotopes are atoms with the same atomic number with different mass numbers.

Here, in these two isotopes of Chlorine, the atomic number is the same and it is equal to 17

Since atomic number is equal to the number of protons or electrons in an atom

Number of protons in both these isotopes = 17

Also, the number of electrons in both these isotopes = 17

The mass number of ₁₇Cl³⁵ = 35

The mass number of  ₁₇Cl³⁷ = 37

Since mass number is defined as the sum of protons and neutrons in the nucleus of the atom

In the case of  ₁₇Cl³⁵,

Number of protons +Number of neutrons = 35

17 +Number of neutrons = 35

Number of neutrons = 35 -17 = 18

In the case of  ₁₇Cl³⁷,

Number of protons +Number of neutrons = 37

17 +Number of neutrons = 37

Number of neutrons = 37 -17 = 20

₁₇Cl³⁵

Number of protons = 17

Number of Electrons = 17

Number of neutrons = 18

₁₇Cl³⁷

Number of protons = 17

Number of Electrons = 17

Number of neutrons = 20

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