Question

number of electrons that F(z=9) has in p-orbitals is equal to: (i) number of electrons in s orbitals in Na (11e) (ii)number of electrons in d orbital (iii) number of electrons in d orbital in Mn (25e) (iv) A,B and C are true

Answer 1

electronic configuration of fluorine

1s² 2s² 2p5

(i) electronic configuration of Na(11e-)

1s2 2s2 2p6 3s1

total no of e- in s - orbital

=1s +2s+3s

=2+2+1

=5

(iii) electronic configuration of Mn

1s2 2s2 2p6 3s2 3p6 4s2 3d5

no of e- in d orbital=5

sorry but I didn't understand second option

but as a first statement and third statement both are true in think the answer must be iv

I hope this helps,( ╹▽╹ )