Question

number of fe atom in hundred gram haemoglobin if it contains 0.33 percentage fe.​

Answer 1

in 100gm of haemoglobin 0.33 percent is fe

so 0.33×100/100= 0.33g

now 1 mole of iron =55.8g

no.of fe in 55.8g is 6.022×10^23

no. of fe in 1g =( 6.022×10^23)/58.5

now, no. of fe in 0.33g is

(6.022×10^23)×0.33/58.5

=6.022×10^23×5.64×10^-3

=33.96 ×10^20

= 3.39×10^21

~3.4 ×10^21 (approx )