Number of Fe atoms in 100 gm of haemoglobin if it contains 0.33 %Fe
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Mass of hemoglobin = 100 gm
Mass of Fe present = 0.33% x 100
=0.33 gm
Atomic mass of Fe = 56 u
56 g of Fe contains = 6.022 x 10²³ atoms of Fe
0.33 g of Fe contains = 6.022 x 10²³/56 x 0.33
=3.5486 x 10²¹ atoms of Fe
Hope it helps you.
^_^
Mass of Fe present = 0.33% x 100
=0.33 gm
Atomic mass of Fe = 56 u
56 g of Fe contains = 6.022 x 10²³ atoms of Fe
0.33 g of Fe contains = 6.022 x 10²³/56 x 0.33
=3.5486 x 10²¹ atoms of Fe
Hope it helps you.
^_^
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