Question

Number of Fe atoms in 22.4 g haemoglobin if it contains 0.25% Fe (Atomic mass of Fe = 56) is ​

Answer 1

We have to find the number of Fe atoms in 22.4 g haemoglobin if it contains 0.25 % Fe.

solution : haemoglobin contains 0.25 % Fe.

∴ mass of Fe in haemoglobin = 0.25% of 22.4 g

= 0.25/100 × 22.4 g

= 0.056 g

no of moles of Fe = given mass/atomic mass of Fe

= 0.056/56

= 0.01 mol

now number of Fe atoms = no of moles of Fe × Avogadro's number

= 0.01 × 6.023 × 10²³

= 6.023 × 10²¹

Therefore the number of Fe atoms in 22.4 g Haemoglobin is 6.023 × 10²¹

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