Math, asked by susmitakumarimdp1985, 9 months ago

number of feal roots of equation x^4+x^2-12=0​

Answers

Answered by thekarthiktangirala
1

Answer:

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Step-by-step explanation:

Answered by Anonymous
1

x^4-x^2-12=0

(x^2-4)(x^2+3)=0

x^2-4=0

(x-2)(x+2)=0

x-2=0

x=2 (real)

x+2=0

x=-2 (real)

x^2+3=0

x^2=-3 will yield imaginary roots

Answered by Anonymous
3

x^4-x^2-12=0

(x^2-4)(x^2+3)=0

x^2-4=0

(x-2)(x+2)=0

x-2=0

x=2 (real)

x+2=0

x=-2 (real)

x^2+3=0

x^2=-3 will yield imaginary roots

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