Question

Number of fundamental particles in 16g of O2^-2

Answer 1

In 1 mole of oxygen there are are 16gm but in 1/2 8gm
So e = 16+2=18
P=16
N=16

Answer 2

Answer:

Number of fundamental particles in 16g of O₂²⁻ ions is equal to 150.57 × 10²³.

Explanation:

As we know that protons, neutrons and electrons are the fundamental particles of an atom.

One oxygen atom has protons = 8, electrons = 8 and neutrons =8

Here given O₂²⁻ ion which has protons = 16, neutrons = 16 and electrons = 16 + 2 = 18

One O₂²⁻ ion has number of fundamental particles $= 16+ 16+ 18 =50$

32g of O₂²⁻ has number of ions = 6.023 × 10²³  O₂²⁻ ions

16g of O₂²⁻ has number of ions $=\frac{16}{32}\times 6.023\times 10^{23} = 3.011\times 10^{23}$

Number of fundamental particles in 3.011× 10²³ O₂²⁻ ions :-

$= 50 \times 3.01 \times 10^{23}$

$= 150.57 \times 10^{23}$ fundamental particles

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