number of glucose molecules present in 10 ml of decimolar solution is? ???
Answers
Answered by
3
Answer:
Explanation:
M = n/V
n = MV
n = 0.1 * 10 * 10^-3
n = 10^-3 mol
Number of molecules = 10^-3 * 6 * 10^23 = 6 * 10^20
Answered by
2
Answer:
M = n/V
n = MV
n = 0.1 * 10 * 10^-3
n = 10^-3 mol
Number of molecules = 10^-3 * 6 * 10^23 = 6 * 10^20
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