Question

Number of gm atoms of Sulphur present in so2 gas which occupy 22.7 ml at stp

Answer 1

Molar mass of the SO₂ = 64 g/mole.

We know, One mole of SO₂ Occupies the volume of 22.4 l.
∵  22.4 liters of Sulphur dioxide at S.T.P. weighs 64 g.
∴ 1 l of the SO₂ weighs 64/22.4 = 2.86 g.
∴  0.227 l of Sulphur Dioxide weighs 2.86 × 0.227 g.= 0.64922 g.

Now, 64 g of Sulphur dioxide contains 32 g of Sulphur.
∴ 0.64922 g of SO₂ Contains 0.64922/2 g = 0.32 g of S.   

Now, Using the Formula,
 No. of gm atoms = Mass/At. mass.
  = 0.32/32
  = 0.01 gm atoms.

Hence, the number of gm atoms of the Sulphur in 27 m of Sulphur dioxide is 0.01.

Hope it helps.