Question

Number of gm of oxygen in 32.2 g na2so4.10h2o is

Answer 1

Number of gm of oxygen in 32.2 g na2so4.10h2o is No. of oxygen atoms in one molecule =4+10=14
Thus moles of oxygen in n moles of compound=n*14
Molar mass of Na2SO4.10H2O=46+32+64+180=322g/mol

Thus
 32.2g=32.2/322=0.1 mols32.2g=32.2/322=0.1mols  

Thus moles of O=0.1*14=1.40.1∗14=1.4 
So weight is 

16*1.4=22.4g16∗1.4=22.4g 

Answer 2

Answer:

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