Chemistry, asked by tghodke58, 7 months ago

Number of gram atoms present in 0.3 mole of (COOH) .2H O is

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Answered by drishtisingh156

the number of gram atoms of oxygen present in 0.3 moles of oxalic acid dihydrate is 0.3×6= 1.8 .

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Answered by Anonymous

Explanation:

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Number of gram atoms present in 0.3 mole of (COOH) .2H O is​

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the number of gram atoms of oxygen present in 0.3 moles of oxalic acid dihydrate is 0.3×6= 1.8 .

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Number of gram atoms present in 0.3 mole of (COOH) .2H O is