Chemistry, asked by vandanakaushik4272, 1 year ago

Number of gram molecules of oxygen in 6.02 x 1024 co

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Answered by asmit56
2

Answer:

1 mole CO equivalent to 6.02x10^23molecules of CO contain 6.02x10^23atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.

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