Question

Number
of
grams
of oxygen
in 32.29 Na2 SO4.10H2O is​

Answer 1

Number of gm of oxygen in 32.2 g Na 2SO4.10H2O is No. of oxygen atoms in one molecule = 4+10 = 14

Thus moles of oxygen in n moles of compound = 14n

Molar mass of Na2SO4.10H2O = 46+32+64+180 = 322g/mol

Thus , $$32.2g= \dfrac{32.2}{322}=0.1\ mols$$

Thus moles of O=0.1×14=1.4So weight is 16×1.4 = 22.4g

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