Question

number of hydrogen atoms in 2.3g of ethanol c2h5oh

Answer 1

Thus 2.3 g / 46 g / mol = 0.05 moles 

0.05 moles * 6.02 x 10E23 molecules per mole (Avogadro number) = 30100000000000000000000 molecules of C2H5OH 

Thus, as you have 6 atoms of hydrogen per molecule, you have then 6 * 30100000000000000000000 = 

180600000000000000000000 atoms of hydrogen

Answer 2

Answer:

The number of hydrogen atoms present in $2.3g$ of ethanol ( $C_{2}H_{5}OH$ ) calculated is $18.066\times 10^{22}$ atoms.

Explanation:

Given data,

The mass of ethanol ( $C_{2}H_{5}OH$ ) = $2.3g$

The number of hydrogen atoms present in $2.3g$ of ethanol ( $C_{2}H_{5}OH$ ) =?

Firstly, we have to calculate the molar mass of the ethanol:

• The molar mass of $C_{2}H_{5}OH$ = ( 2 × carbon's atomic mass ) + ( 6 × hydrogen's atomic mass ) + ( 1 × oxygen's atomic mass )
• The molar mass of $C_{2}H_{5}OH$ = $(2\times 12) + ( 6\times 1 ) + ( 1\times 16 )$ = $46g/mol$.

Now,

• The number of moles of ethanol ( $C_{2}H_{5}OH$ ) = $\frac{given mass}{molar mass}$ = $\frac{2.3}{46}$ = $0.05mol$.

As we know,

• $1mole$ = $6.022\times 10^{23} molecules$

So,

• $0.05moles$ = $0.05\times 6.022\times 10^{23}$ = $3.011\times 10^{22}$ molecules.

One ethanol ( $C_{2}H_{5}OH$ ) molecule has 6 hydrogen atoms.

Thus,

• $3.011\times 10^{22}$ molecules = $6\times 3.011\times 10^{22}$ atoms = $18.066\times 10^{22}$ atoms.

Hence, the number of hydrogen atoms present in $2.3g$ of ethanol = $18.066\times 10^{22}$ atoms.