Question

number of integers between 2019 and 2020​

Answer 1

Answer:

2019 = -1 (mod 2020)

=> 2019 when raised to an even power gives 1 (mod 2020) and gives -1 (mod 2020) when raised to an odd power.

( 2019^2n = -1^2n (mod 2020) = 1(mod 2020).

2019^(2n+1) = -1^(2n) *-1 (mod 2020) = -1(mod2020)

) => 2019^2019 = -1 (mod 2020) = 2019 .  

Therefore, 2019^2019 leaves a remainder of 2019 when divided by 2020.

Answer 2

Questions is wrong

pls mark as brainlist