Question

Number of integral values of x, satisfying
|x2−3x+2x/2−5x+4|=|3x−x2+2x/2−5x+4|

Answer 1

i think so it is

《23+34+5×6/64=6|46~56×5×4×+34

Answer 2

Answer :

Hey mate, here's your answer

x² - 3x + 2x / 2 - 5x + 4 = 3x - x² + 2x / 2 - 5x + 4

If mate this is your question then here's your answer

x² - 3x + 2x = ( 3x - x² + 2x / 2 - 5x + 4 ) × 2 - 5x + 4

x² - 3x + 2x = 3x - x² + 2x

x² + x² - 3x - 3x = 2x - 2x

2x² - 6x = 0

2x (x - 3) = 0

x - 3 = 0

x = 3

PLEASE MARK AS THE BRAINLIEST