Question

number of ions in one ml of 0.1M baruim nitrate solution

Answer 1

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So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is 

So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is 18.06 * 10^23 = 1.806 * 20^24 ions. 

So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is 18.06 * 10^23 = 1.806 * 20^24 ions. But the concentration is 0.1 Molar, so there are 1.806*10^23 ions in a liter of 0.1 Molar Barium Nitrate 

So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is 18.06 * 10^23 = 1.806 * 20^24 ions. But the concentration is 0.1 Molar, so there are 1.806*10^23 ions in a liter of 0.1 Molar Barium Nitrate But you want to know the amount in 1/1000 of a liter, so that is 

So, 1 mole in a liter has 6.02 * 10^23 'particles' of Ba(N03)2, each 'particle' has 3 ions, so the total numer of ions is 18.06 * 10^23 = 1.806 * 20^24 ions. But the concentration is 0.1 Molar, so there are 1.806*10^23 ions in a liter of 0.1 Molar Barium Nitrate But you want to know the amount in 1/1000 of a liter, so that is 1.806*10^20 ions. 

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