number of iron atoms in 100g haemoglobin if it cotains 0.33% iron.
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Answered by
452
hiiii,
Mass of Haemoglobin =100 g
Mass of iron atoms = (0.33/100) x 100 =0.33 g
56 g of iron contains = 1 mole of Iron or 6.023 x 1023 atoms
0.33 g of iron contains = (0.33 x 6.023 x 1023)/56 = 3.5492 x 1021 atoms of Fe.
hope it helps you!!
Mass of Haemoglobin =100 g
Mass of iron atoms = (0.33/100) x 100 =0.33 g
56 g of iron contains = 1 mole of Iron or 6.023 x 1023 atoms
0.33 g of iron contains = (0.33 x 6.023 x 1023)/56 = 3.5492 x 1021 atoms of Fe.
hope it helps you!!
Anonymous:
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Answered by
165
Given :
100g of haemoglobin
Mass of Iron(Fe)=0.33%=(0.33/100)x100=0.33g
1mole of Iron contains=56g
56g of iron contains 6.022 x 10 ²³ Fe atoms.
so, 0.33 g of Iron --------?
=0.33 x 6.022 x10²³/56
=0.035486 x10²³
=35.486 X 10 ²¹ Fe atoms.
∴ 0.33 g of Fe contains 35.486 X 10 ²¹ Fe atoms.
100g of haemoglobin
Mass of Iron(Fe)=0.33%=(0.33/100)x100=0.33g
1mole of Iron contains=56g
56g of iron contains 6.022 x 10 ²³ Fe atoms.
so, 0.33 g of Iron --------?
=0.33 x 6.022 x10²³/56
=0.035486 x10²³
=35.486 X 10 ²¹ Fe atoms.
∴ 0.33 g of Fe contains 35.486 X 10 ²¹ Fe atoms.
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