Chemistry, asked by sneha09, 1 year ago

number of iron atoms in 100g haemoglobin if it cotains 0.33% iron.

Answers

Answered by Anonymous
452
hiiii,

Mass of Haemoglobin =100 g
Mass of iron atoms = (0.33/100) x 100 =0.33 g

56 g of iron contains = 1 mole of Iron or 6.023 x 1023 atoms

0.33 g of iron contains = (0.33 x 6.023 x 1023)/56 = 3.5492 x 1021 atoms of Fe.


hope it helps you!!

Anonymous: okkkk
Anonymous: but i got that much
sneha09: oh.. I'm really sorry i thought it was 1021 written there instead of 10^21 I'm sorry once again
sneha09: and yeah thanks for the help
Anonymous: its okay
Anonymous: welcome!!!
sneha09: so nice of you
Anonymous: thank you!!!
rkphysics03raju: Thnxs alot
Anonymous: ur welcome!!!!!
Answered by prmkulk1978
165
Given :
100g of haemoglobin
Mass of Iron(Fe)=0.33%=(0.33/100)x100=0.33g
1mole of Iron contains=56g
56g of iron contains 6.022 x 10 ²³ Fe atoms.
so, 0.33 g of Iron --------? 
=0.33 x 6.022 x10²³/56
=0.035486 x10²³
=35.486 X 10 ²¹ Fe atoms.
∴ 0.33 g of Fe contains 35.486 X 10 ²¹ Fe atoms.

rkphysics03raju: Thanks
Similar questions