Question

number of isomers of pt(nh3)2cl2 is a)3 b)4 c)2 d)5​

Answer 1

We have to find the no of isomers of Pt(NH₃)₂Cl₂.

solution : Pt(NH₃)₂Cl₂ exists in square planner geometrical shape. there are two ammonia and two chlorine attaching with platinum. so the general form of this compound is MA₂B₂. we know, this type of structure can be shaped into two forms cis and trans. see figure to understand.

Therefore no of isomers of Pt(NH₃)₂Cl₂ is two i.e., cis Pt(NH₃)₂Cl₂ and trans Pt(NH₃)₂Cl₂.

also read similar questions : Which of the following can't show isomerism ?

(1) [Ni(NH3)2Cl2]

(2) [Ni(en)3]

(3) [Pt(NH3)2Cl2]

(4) [Na(NH3)4(H20)2]

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iupac name of pt(nh3)2cl2(no2)

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