Number of lone pairs of electrons in 9 gms. of water are [N = Avogadro
Number]
1) 2N
2) N/2
3) N
4) N /4
Answers
Answered by
15
Answer:
The Lewis structure for water is comprised of a polar covalent bond with 2 lone pairs (situated on the oxygen atom).
n (moles) =m(mass)/M(molar mass)
M of water: 18.015 g*mol^-1
m, obviously, is as given: 9 grams;
Therefore,
n=9grams/18.015g*mol^-1 = 0.5 mol (H2O)
Total number of lone pairs is then: 0.5*2*6.0221*10e+23 = 6.0221*10^23 lone
Answered by
6
Answer:
n= 9/18= 0.5 moles
no.of lone pairs = N ×0.5× 2 = N
your answer is 3
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