English, asked by lovaraju887, 9 months ago

Number of lone pairs of electrons in 9 gms. of water are [N = Avogadro
Number]
1) 2N
2) N/2
3) N
4) N /4​

Answers

Answered by kameenaDEVIL
15

Answer:

The Lewis structure for water is comprised of a polar covalent bond with 2 lone pairs (situated on the oxygen atom).

n (moles) =m(mass)/M(molar mass)

M of water: 18.015 g*mol^-1

m, obviously, is as given: 9 grams;

Therefore,

n=9grams/18.015g*mol^-1 = 0.5 mol (H2O)

Total number of lone pairs is then: 0.5*2*6.0221*10e+23 = 6.0221*10^23 lone

Answered by Tirth7404
6

Answer:

n= 9/18= 0.5 moles

no.of lone pairs = N ×0.5× 2 = N

your answer is 3

please mark as brainliest if it is helpful to you

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