Chemistry, asked by raodheeraj55, 1 month ago

Number of lone pairs of Urotropine is??
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Answers

Answered by AbhiThakur07
0

Explanation:

=>According to the structure, there are zero N−N bonds present in the structure.

Answered by Sreejanandakumarsl
0

Answer:

Number of lone pair present in Urotropine is four.

Explanation:

  • We can see that in the structure of Urotropine (image attached) there are 4 nitrogen atoms, although their valency is fulfilled, that is, they have bonded with three other atoms, yet they still have something called as lone pair attached to them.
  • Each nitrogen atom contains one lone pair even after completing their valency, therefore in the structure there are 4 nitrogen’s, hence there are 4 lone pairs in total present in the structure of urotropine.
  • The formula for urotropine is (CH2)6N4. It is a heterocyclic organic compound.
  • The structure indicates that there are no N-N bonds in the system.
  • Methenamine, hexamine, and urotropin are other names for hexamethylenetetramine, a heterocyclic organic molecule with the formula (CH2)6N4.
  • This white crystalline substance is very soluble in polar organic solvents and water.
  • Its cage-like structure is comparable to that of adamantane.
  • It is helpful in the production of other organic molecules, such as additives for rubber, plastics, and medications. At 280 °C, it sublimes in vacuum.

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