Chemistry, asked by vinaysurana, 5 months ago

number of molecule present in 10 gram of water​

Answers

Answered by TheJagirdaR
2

Answer:

\textit {10 g of H2O cotains =6.022×102318×10 = 3.34×1023 molecules.}

6.022×102318×10 = 3.34×1023 molecules.

Answered by dadsdaughter
0

Answer:

3.34*10^23

Explanation:

Molar mass of water=18 gm.mol^-1

18gms of water contains 6.022*10^23 molecules

10gms of water contains={(6.022*10^23)*10]/18

=3.34*10^23molecules.

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