Question

Number of molecules among the following having non-zero dipole moment is:
03, S03, SF4, SF,H2S, CS, SO2, H20 and H202
Backspace
7
8
9
5
6.
1 2 3
0​

Answer 1

Answer:

the structure given). So, its dipole moment is non-zero. CH

4

and BF

4

−

occupy regular tetrahedron structures. In these molecules, vector sum of dipole moment of the first three bonds will be cancelled by the the dipole moment of 4

th

bond.

In C

2

H

6

, the dipole moment of the 1

st

carbon atom is cancelled by the dipole moment of the 2

nd

carbon atom.

Explanation:

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Answer 2

Answer:

SO3,SF6,CS2 are molecules with symmetrical shapes and have zero dipole moment.

Explanation:

Hint : A molecule is said to be having non-zero dipole moment when the distribution of its substituent atoms is such that there is a net resultant force that is not equal to zero and thereby is pointing into certain direction, i.e. either toward or away from the atom. This uneven distribution of polar power/ polarity gives rise to the dipole moment.

A) $O_{3}$ According to valence bond theory, the ozone molecule consists of a central oxygen atom bonded to 2 oxygen atoms in angular fashion with almost 120 degrees between the 2 bonds. One single and one double bond between the central oxygen and the flanking oxygens exchange positions, forming a resonance structure. The central oxygen has one formal + charge while the other oxygens share a negative charge between. Thus, ozone has a permanent dipole moment.

B) $SO_3$ is a trigonal planar molecule, which can be derived from its Lewis structure. Each sulfur-oxygen bond is polar from S to O, but the three bonds are equally polar and are pointed in symmetrical opposition so that they cancel. The SO3 molecule has a dipole moment of zero.

C) $SF_4$

The fluorine is more electronegative than the sulphur atom. so, the dipole moment will direct towards the fluorine atom. Since the dipole moment of one fluorine atom is cancelled by resultant dipole moments of the other fluorine, and the lone pair does not get cancelled out. Hence it has a non zero dipole moment.

D) SF

Since the dipole moment of one fluorine atom is cancelled by resultant dipole moments of the other fluorine, and the lone pair does not get cancelled out. Hence it has a non zero dipole moment.

E) H2S molecule has an angular geometry because it has two lone pairs of electrons that make the molecule bend. The dipole moment is not zero. This is because sulphur is more electronegative than hydrogen, making the molecule slightly polar.

F) CS2 (Carbon disulfide) is nonpolar because of its symmetric (linear) shape. Although carbon and sulfur differ in their electronegativity and C-S bond is polar, the polarity of both opposite C-S bonds gets canceled by each other resulting in a nonpolar molecule.

G) SO2 is polar in nature because of the difference in electronegativity between sulfur and oxygen atoms. The greater the difference in electronegativity more will be the polarity of the molecule. The bent shape of SO2 is because of the repulsion between the unbonded electrons present on the sulfur and oxygen atoms. The unsymmetrical shape also identifies whether a molecule is polar or not.

H) H2O In a triatomic H2O water molecules, the dipole moment is 1.84D. Due to the bent structure of the water molecule, the dipole moment is not zero. This is due to the resultant dipole moments of 2 O-H bonds, inclined at 104.5 degrees, with 2 lone pairs on oxygen atoms.

I) H202

H2O2 is polar in nature due to its bent shape geometry. The O-H bonds result in a net dipole moment because of the difference between the electronegativity of hydrogen(2.2) and oxygen(3.44) atom. The oxygen atoms being more electronegative becomes a negative pole and hydrogen atoms side as a positive pole with a net dipole moment 2.26 D.

SO3,SF6,CS2 are molecules with symmetrical shapes and have zero dipole moment.