Question

Number of molecules in 1 L water is close to (density of H2O = 1 g/ml)

Answer 1

Answer:

By mole concept, we know that 1 mole molecule of any substance has avogadro number of molecules(6.022*10^23). So we need to find the moles of water in 1 L of water or 1000mL of water. Taking the density of water to be 1g/mL, 1000mL of water= 1000g water. =3.34*10^25 molecules of water.

Explanation:

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Answer 2

Answer:

Density of H2O is 1g/ml

Therefore mass in 1000ml will be 1g * 1000 =1000g

No. of moles in 1000g of water =

$\frac{1000g}{18g \:{mol}^{? \\ - 1} } = 55.5 \: mol$

1 mole molecules of water =

$6.022 \times {10}^{23}$

Therefore 55.5 moles molecules of water =

$55.5 \times 6.022 \times {10}^{23} = 334.22 \times {10}^{23} molecules \:$