Question

number of molecules in 22.4l of nitrogen gas at stp

Answer 1

Hi mate.

Thanks for asking this question.

Here Here is your answer,


Given =

V= 22.4 lit.


We know that,


$n = \frac{v}{22.4 \: lit}$


$n = \frac{22.4}{22.4}$


$n = 1 \: mole$




For the total number of molecules,

We have,


$no. \: of \: molecule = n \: \times avag. \: no.$


$no. \: of \: molecules = 1 \times 6.022 \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {10}^{23}$


$no. \: of \: molecules = 6.022 \times {10}^{23}$







Thank you.





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