Question

number of molecules of compund H2C2O4.2H2O present in the pure sample of 192 grams oxygen​

Answer 1

Explanation:

Oxalic acid dihydrate is C

2

H

2

O

4

.2H

2

O

One molecule of Oxalic acid dihydrate contains 6 oxygen atoms

1 mol of Oxalic acid dihydrate contains 6×N

A

atoms of oxygen

i.e. 6×6.022×10

23

=36.13×10

23

atoms

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Answer 2

Answer:

The number of molecules of the compound $H_{2}C_{2}O_{4} .2H_{2}O$ present in the pure sample of $192g$ of oxygen is $12.044\times 10^{23}$ molecules.

Explanation:

Given,

The mass of oxygen = $192g$

The number of moles of compound $H_{2}C_{2}O_{4} .2H_{2}O$ present in $192g$ of oxygen =?

As we know,

• The molar mass of oxygen = $16g/mol$

Therefore,

• The number of moles of oxygen = $\frac{Given mass }{Molar mass}$ = $\frac{192}{16}$ = $12 mol$.

Thus, the pure sample of $192g$ contains $12 moles$ of oxygen.

Now, from the given compound, $H_{2}C_{2}O_{4} .2H_{2}O$, we can say that:

• In $1 mole$ of the compound $H_{2}C_{2}O_{4} .2H_{2}O$, $6 moles$ of oxygen are present.

Therefore,

• $1 mole$ of oxygen = $\frac{1}{6} moles$ of compound $H_{2}C_{2}O_{4} .2H_{2}O$.
• $12 moles$ of oxygen = $\frac{1}{6}\times 12$ = $2 moles$ of compound $H_{2}C_{2}O_{4} .2H_{2}O$.

As we know,

• $1 mole$ = $6.022\times 10^{23}$ molecules
• $2 moles$ = $2 \times 6.022\times 10^{23}$ = $12.044\times 10^{23}$ molecules.

Hence, the number of molecules of the compound $H_{2}C_{2}O_{4} .2H_{2}O$ present in the pure sample of $192g$ of oxygen is $12.044\times 10^{23}$ molecules.