Question

number of molecules of methyl alcohol (CH3OH) present in 50 ml of 2.0M aqueous solution is​

Answer 1

Answer: 0.622 × 10^23

Explanation: M = 2

So, 2 = n × 1000/ 50

n = 0.1

therefore, no of molecule = 0.1 × NA

0.1 × 6.022 × 10^23

=> 0.6022×10^23

Answer 2

Answer: 0.622 × 10^23

Explanation: M = 2

So, 2 = n × 1000/ 50

n = 0.1

therefore, no of molecule = 0.1 × NA

0.1 × 6.022 × 10^23

=> 0.6022×10^23