Question

Number of molecules of oxygen gas that occupies a volume of 224ml at 273k and 3 atm pressure

Answer 1

Answer:

Hey buddy here is your answer:-

Explanation:

22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 ×3/1= 67200 ml at STP.

So 224 ml of oxygen at 273 K and 3-atm = 224 ×3= 672 ml at STP

The number of Oxygen molecules present in 22400 ml of gas at STP=N

(where N= Avagadro Number)

Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =N×672/22400 × N molecules.

=3/100×6.022×1023

=18.066×1021 Molecules =1.8066×1022 molecules

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